225x^2+390x+169=0

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Solution for 225x^2+390x+169=0 equation: 



225x^2+390x+169=0

a = 225; b = 390; c = +169;
Δ = b2-4ac
Δ = 3902-4·225·169
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-390}{450}=-13/15$

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